Question

A spinner is divided into many sections of equal size. Some sections are red, some are blue, and the remaining are green. The probability of the arrow landing on a section colored red is 9 over 20. The probability of the arrow landing on a section colored blue is 6 over 20. What is the probability of the arrow landing on a green-colored section?.

Answer 1

The answer would be 5/20 because you add the probability of red and blue (15/20), then subtract from the total (20) which would make it 5/20.

Answer 2

Answer: Probability of the arrow landing on a green colored section is $\dfrac{1}{4}$

Step-by-step explanation:

Since we have given that

Probability of the arrow landing on a section colored blue = $\dfrac{6}{20}$

Probability of the arrow landing on a section colored red = $\dfrac{9}{20}$

Since there are only three sections i.e. red, blue and green.

We need to find the probability of the arrow landing on a section colored green.

Required probability is given by

$1-(\dfrac{9}{20}+\dfrac{6}{20})\\\\=1-\dfrac{15}{20}\\\\=\dfrac{20-15}{20}\\\\=\dfrac{5}{20}\\\\=\dfrac{1}{4}$

Hence, Probability of the arrow landing on a green colored section is $\dfrac{1}{4}$