Question

A right triangle has legs measuring 18 in. and 26 in.

What is the length of the hypotenuse?

Round to the nearest tenth.

18.8 in.

31.6 in.

44.0 in.

100.0 in.

Answer 1

18^2 + 26^2 = c^2

c^2 = 1000

c = 10sqrt10 (decimal: 31.62)

Answer 2

By using Pythagorean's theorem we will see that the hypotenuse measures 31.6 inches.

How to find the length of the hypotenuse?

By Pythagorean's theorem, we know that for all right triangles the sum of the squares of the legs is equal to the square of the hypotenuse.

So, if we define H as the hypotenuse, we can write:

$H^2 = (18in)^2 + (26in)^2$

Solving for H, we get:

$H = \sqrt{(18in)^2 + (26in)^2} = \sqrt{1,000 in^2} = 31.6 in$

So we conclude that the hypotenuse measures 31.6 inches.

If you want to learn more about right triangles:

https://brainly.com/question/2217700

#SPJ2