Question

What is the product?
A. $\frac{k+1}{k^2}$
B. $\frac{k-1}{k^2}$
C. $\frac{-1}{k}$
D. $\frac{1}{k}$

Answer 1

$\dfrac{3k}{k+1}\cdot\dfrac{k^2-1}{3k^3}=\dfrac{3k(k+1)(k-1)}{3k^3(k+1)}=\dfrac{k-1}{k^2}$

Answer B.