The solution to the system of equations y = x² - 2x - 15 and y = 8x - 40 is (5,0)
The equations are given as:
y = x² - 2x - 15
y = 8x - 40
Substitute y = 8x - 40 in y = x² - 2x - 15
8x - 40 = x² - 2x - 15
Collect like terms
x² - 2x - 8x - 15 + 40 = 0
Evaluate
x² - 10x + 25 = 0
Factorize the equation
(x - 5)(x - 5) = 0
Solve for x
x - 5 = 0 and x - 5 = 0
This gives
x = 5
Substitute x = 5 in y = 8x - 40
y = 8 * 5 - 40
y = 0
Hence, the solution to the system of equation is (5,0)
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