Question

A student determines that she used 0.0665 mol of sodium hydroxide (NaOH) to completely titrate 25.00 mL of sulfuric acid solution (H2SO4). What is the molarity of the sulfuric acid?
0.00131 M
0.00262 M
1.31 M
2.62 M

Answer 1

For a titration procedure, one must know the reaction going on in the steps involved. For this case, it is the reaction between NaOH and sulfuric acid.

2NaOH + H2SO4 = Na2SO4 + 2H2O

With the reaction and the values given we calculate as follows:

0.0665 mol NaOH ( 1 mol H2SO4 / 2 mol NaOH ) = 0.03325 mol H2SO4

Molarity = 0.03325 / .025 = 1.33 M