ok, diameter
find the distance and the midpoint
remember, the equation of the circle with center (h,k) and radius r is
(x-h)²+(y-k)²=r²
so find radius and midpoint
find diameter
find distance between the points
D=[tex] \sqrt{(x2-x1)^2+(y2-y1)^2} [/tex]
D=[tex] \sqrt{(5-(-3))^2+(7-1)^2} [/tex]
D=[tex] \sqrt{(5+3)^2+(6)^2} [/tex]
D=[tex] \sqrt{(8)^2+36} [/tex]
D=[tex] \sqrt{64+36} [/tex]
D=[tex] \sqrt{100} [/tex]
D=10
radius is 5 then
midpoint is the average of the points
(-3+5)/2 is the x value which is 1
(1+7)/2 is theh y vale which is 4
center is (1,4)
radius is 5
(x-1)²+(y-4)²=5² is da equation
