Question

Lucas has an 11 ft ladder. To the nearest foot, how far up the wall will the ladder reach when the base of the ladder is 4 ft from the wall?

Answer 1

It would be about 10.24 ft because if we use the A squared +B squared= C squared we can input the known values so it would look something like this... 4 squared+ B squared = 11 squared and then we isolate B to get about 10.24 ft 

Answer 2

Lucas has an 11 ft ladder and the base of the ladder is 4 ft from the wall.

Thus, the wall will be 10.5 ft far.

What is Pythagoras's Theorem?

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

$|AC|^2 = |AB|^2 + |BC|^2$

where |AB| = length of line segment AB. (AB and BC are the rest of the two sides of that triangle ABC, AC being the hypotenuse).

Lucas has an 11 ft ladder and the base of the ladder is 4 ft from the wall.

So, we need to find the height of the wall.

By Pythagoras' theorem,

$|AC|^2 = |AB|^2 + |BC|^2\\\\|11|^2 = |AB|^2 + |4|^2\\\\|AB|^2= 121 - 16\\\\|AB|^2 = 105\\\\AB = 10.5$

Learn more about Pythagoras' theorem here:

https://brainly.com/question/12105522

#SPJ2