Question

A 55.0-g piece of copper wire is heated, and the temperature of the wire changes from 19.0 c to 86.0 c. The amount of heat absorbed is 343 cal. What is the specific heat of copper? Show work

Answer 1

Q = mass x specific heat x delta T 343 = 55.0 x specific heat ( 86.0 - 19.0 ) 343 = 3685 x specific heat specific heat = 0.0931 cal /g°C

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Your answer is: 0.0931 cal/g degrees C

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Answer 2

The specific heat of copper wire has been $\rm \bold{0.093\;cal/g^\circ C}$.

Specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

$\rm Heat=mass\;\times\;specific\;heat\;\Delta \textit T$

Computation for specific heat of copper

The given copper wire has a mass of 55 g.

The heat absorbed by the wire has been 343 cal.

The change in temperature ($\Delta T$) for wire has been given by:

$\Delta T= \text{Final temperature - Initial temperature}\\ \Delta T=86-19^\circ \text C\\ \Delta T=67^\circ \text C$

Substituting the values for the specific heat of copper:

$\rm 343\;cal=55\;g\;\times\;specific\;heat\;\times\;67^\circ C\\\\ Specific\;heat=\dfrac{343}{55\;\times\;67}\;cal/g^\circ C\\\\ Specific\;heat=0.093\;cal/g^\circ C$

The specific heat of copper wire has been $\rm \bold{0.093\;cal/g^\circ C}$.

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