1.
[tex]r=32\,\text{units}\\\\
A=\pi\cdot r^2=\pi\cdot32^2=1024\pi\,\,\text{units}^2[/tex]
Answer D.
2.
From secant theorem, we know, that:
[tex]|AE|\cdot|BE|=|DE|\cdot|CE|[/tex]
and from picture:
[tex]|BE|=x+1\\\\|CE|=x+4\\\\|AE|=11+x+1=x+12\\\\|DE|=1+x+4=x+5[/tex]
So we can calculate:
[tex]|AE|\cdot|BE|=|DE|\cdot|CE|\\\\(x+12)\cdot(x+1)=(x+5)\cdot(x+4)\\\\
x^2+12x+x+12=x^2+5x+4x+20\\\\
x^2+13x+12=x^2+9x+20\quad|-x^2\\\\13x+12=9x+20\quad|-9x\\\\4x+12=20\quad|-12\\\\4x=8\quad|:4\\\\\boxed{x=2}[/tex]