Question

the line has the same slope as 7x-y=5 and the same y intercept as the graph 3y-11x=15

write an equation of the line in standard form

Answer 1

7x - y= -5. Standard form is when it is written with x and y on the same side, but x is not negative or a fraction. To find the slope and y intercept, you must change the first two equations to slope intercept. You get y=7x-5 for the first one and y=11/3x+5 for the seccond equation. Take the 5 as your y intercept and the 7 as your slope and you get y=7x+5. Now you need to change it into standard form. When all is said and done, your final answer should be 7x - y = -5. 

Answer 2

7x - y = 5     (Same slope)     ,    3y - 11x = 15   (Same y-intercept)

So, our first step is to find the slope of the first statement! :)

7x - y = 5

Subtract 7x from both sides, so that it is a y-equals equation.

-y = -7x + 5

Divide both sides by -1.

y = 7x - 5

So, our slope is 7!

3y - 11x = 15

To find the y-intercept, we must get y by itself to make this into a y-equals equation.

So, simply add 11x to both sides!

3y = 11x + 15

Divide both sides by 3.

y = 11/3x + 5

So, our y-intercept is 5!

Slope = 7, y-intercept is 5.

Standard form = Ax + By = C

So, we must first put this into slope-intercept form, which is y=mx+b

Simply plug in the values for m and b.

y = 7x + 5

Subtract 7x from both sides.


-7x + y = 5   

However, in standard form, x can NEVER be negative, so simply divide everything by -1!

7x - y = -5   <=== Standard Form

~Hope I helped!~