we know that
The sum of the internal angles of a triangle must be equal to [tex] 180 [/tex] degrees
see the attached figure with letters to better understand the problem
m∠B+[tex] (6x+1)=180 [/tex]°-----> by supplementary angles
m∠B=[tex] 179-6x [/tex]
m∠A=[tex] 2x+10 [/tex]
m∠C=[tex] 79 [/tex]
m∠A+m∠B+m∠C=[tex] 180 [/tex]
Substitute
[tex] (2x+10)+(179-6x)+79=180\\ -4x+268=180\\ 4x=268-180\\ 4x=88\\ x=22\ degrees [/tex]
therefore
the answer is
the value of x is equal to [tex] 22\ degrees [/tex]
