Question

Two planes left the same airport traveling in opposite directions. The first plane left at 9:00 a.m. and 2.25 h later, the two planes were 1825 mi apart. The second plane left at 10:00 a.m. and its average rate was 108 mph slower than the first plane's average rate. What was the first plane's average rate?

Let x represent the first plane's average rate.

Enter an equation that can be used to solve this problem in the first box. Solve for x and enter the first plane's average rate in the second box.

Equation: ____________

x = ____ mph

Answer 1

Formula for calculating the distance :
d = v * t,  where v is the velocity and t is the time.
We have two planes that are traveling in the opposite directions.
d = 2.25 x + 1.25 * ( x - 108 )
1,825 = 2.25 x + 1.25 x - 135
1,825 + 135 = 3.5 x
x = 1,960 : 3.5
x = 560
Answer:
Equation : 1,825 = 2.25 x + 125 *( x - 135 )
x = 560 mph