Question

I can not figure out how to do this question and I need help please

Answer 1

$\bf \textit{quadratic formula}\\\\ \begin{array}{lcclll} 1x^2&-6x&+12&=0\\ \uparrow &\uparrow &\uparrow \\ a&b&c \end{array} \qquad \qquad x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}$