Respuesta :

irspow
In this format, we can either use latex or enter a "^" to show that we are raising something to a power....

y=2(0.4)^x

This is exponential decay because the rate is less than 1, in this case 0.4.

All exponential functions can be expressed as:

F=Ir^t, F=final amount, I=initial amount, r=rate, t=time
Te way you wrote your equation is confusing & as it is cannot be an exponential function unless it is written as follows:

either y = 2^(0.4)x    or y=2^(0.4)^x

In the first case it's growing as x grow
in the second case is decaying as x is growing.


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