Respuesta :
The given equation, x9 - 5x3 + 6 = 0, is not a quadratic equation because the exponent of the first term is 9 while that of the second term is 3. The square of 3. If we are to square x3, we should only be getting x6 instead of x9. Therefore, the answer is NO.
The equation [tex]x^9 -5x^3+6=0[/tex] is not an quadratic equation because the quadratic equation is in the form [tex]ax^2+bx+c = 0[/tex] where a, b, and c are known constants and 'a' is not equal to zero.
Given :
Equation - [tex]x^9 -5x^3+6=0[/tex]
Following are the key points regarding quadratic equation:
- The quadratic equation are in the form [tex]ax^2+bx+c = 0[/tex].
- Where, a, b, and c are the known constant and 'a' is not equal to zero.
- If a is equal to zero than it becomes linear equation.
- The value of x that satisfy the quadratic equation are known as the root of that equation.
- The value of x is given by-
[tex]x =\dfrac{ -b\pm\sqrt{b^2-4ac} }{2a}[/tex]
From the above points it can be concluded that the given equation [tex]x^9 -5x^3+6=0[/tex] is not an quadratic equation.
For more information, refer the link given below:
https://brainly.com/question/13385331