Question

What is the value of x when 4y = x2?

Answer 1

(I am assuming x2 means x^2 or x squared.)

To solve this your goal is to get x by itself. So,

4y = $x^{2}$

Then square root each side:

$\sqrt{4y} = \sqrt{ x^{2} }$

then it becomes:

$2y= x$

So, x = 2y