Question

You might have a flashlight that runs (2) d-cells of 1.5 volts each in series. the bulb is rated for 0.7 amps. what’s its resistance?

Answer 1

Answer:

The value of resistance is 4.28 Ω.

Explanation:

Voltage of single d-cells = 1.5 V

Two d-cells are in series with in a flashlight.

$V_1= 1.5 V, V_2=1.5 V$

$V= V_1+V_2...V_n$ (series arrangement)

So, Total voltage in the flash light:

V = 1.5 V + 1.5 V = 3.0 V

Electrical Current rating of the bulb I= 0.7 A

let the resistance be R

$V=I\times R$ (Ohms law}

$R=\frac{V}{I}=\frac{3.0 V}{0.7 A}=4.28 \Omega$

The value of resistance is 4.28 Ω.

Answer 2

We have that for the Question "You might have a flashlight that runs (2) d-cells of 1.5 volts each in series. the bulb is rated for 0.7 amps. what’s its resistance" it can be said that The bulbs Resistance is

R=4.3ohms

From the question we are told

You might have a flashlight that runs (2) d-cells of 1.5 volts each in series. the bulb is rated for 0.7 amps. what’s its resistance?

Resistance

Generally the equation for the Resistance R   is mathematically given as

$R=\frac{e_1+e_2}{I}\\\\R=\frac{1.5+1.5}{0.7}$

• R=4.3ohms

Therefore

The bulbs Resistance is

R=4.3ohms

For more information on Resistance visit

https://brainly.com/question/4289257