Question

Write the quadratic equation in general form. what is the value of b 2 - 4ac? 1 = 2x 2 7x 40 41 57

Answer 1

Answer:

$2x^2+7x-1= 0$

$b^2-4ac$ = 57

Step-by-step explanation:

The general form of the quadratic equation is:

$ax^2+bx+c = 0$              ....[1]

Given the equation:

$1 = 2x^2+7x$

Subtract 1 from both sides we have;

$0= 2x^2+7x-1$

or we can write this as:

$2x^2+7x-1= 0$

We have to find the $b^2-4ac$

Compare equation $2x^2+7x-1= 0$ with equation [1]

a = 2 , b = 7 and c = -1

then;

$b^2-4ac = (7)^2-4(2)(-1) = 49+8 = 57$

Therefore, the  quadratic equation in general form is, $2x^2+7x-1= 0$ and the value of  $b^2-4ac$ is, 57