well, as already pointed out, you add the volumes of both, the cylinder and the cone
notice the picture below
so.. now, we know the height of the cone, is about 7.26
thus [tex]\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\qquad
\begin{cases}
r=radius\\
h=height\\
-------\\
r=1\\
h=12.07
\end{cases}\implies V=\pi (1)^2 \cdot 12.07
\\\\\\
\textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\qquad
\begin{cases}
r=radius\\
h=height\\
-------\\
r=9.3\\
h\approx 7.26
\end{cases}\implies V=\cfrac{\pi (9.3)^2\cdot 7.26}{3}[/tex]
