Question

A 3.5 kilogram object is swung in a circular path on the end of a 0.4 meter long string. the object makes one trip around the circle every 0.2 seconds. determine the speed of the object.

Answer 1

Path length is 2*pi*0.4=2.512
Speed=distance/time
Speed =2.512/0.2=12.56m/s

Answer 2

This question involves the concepts of linear speed and time period.

The speed of the object is "12.57 m/s".

STEP 1: We will find the angular speed of the ball:

$\omega = \frac{2\pi}{T}$

where,

• ω = angualar speed = ?

• T = time period = 0.2 s

Therefore,

$\omega = \frac{2\pi}{0.2\ s}$

ω = 31.41 rad/s

STEP 2: We will find the linear speed of the ball:

v = rω

where,

• v = linear speed = ?

• r = radius of circular path = length of string = 0.4 m

Therefore,

v = (0.4 m)(31.41 rad/s)

v = 12.57 m/s

Learn more about time period here:

https://brainly.com/question/87823