Question

Which is the correct mole ratio for aluminum chloride to chlorine in the chemical reaction alcl3 br2 ? albr3 cl2?

Answer 1

To answer this item what needs to be done is to write the correct and balanced chemical reaction as below.
                                      2AlCl3 + 3Br2 --> 2AlBr3 + 3Cl2
From the chemical reaction above, we can say that every 2 moles of AlCl3 will produce 3 moles of Cl2. Thus, the answer is 2:3. 

Answer 2

Answer : The mole ratio for aluminium chloride to chlorine is, 2 : 3

Explanation :

The given unbalanced chemical reaction is :

$AlCl_3+Br_2\rightarrow AlBr_3+Cl_2$

First we have to balance the chemical reaction.

In order to balance the chemical reaction, the coefficient 2 is put before $AlCl_3\text{ and }AlBr_3$ and the coefficient 3 is put before $Cl_2\text{ and }Br_2$.

The given balanced chemical reaction will be :

$2AlCl_3+3Br_2\rightarrow 2AlBr_3+3Cl_2$

By the stoichiometry we can say that, 2 moles of $AlCl_3$ react with 3 moles of $Br_2$ to give 2 moles of $AlBr_3$ and 3 moles of $Cl_2$ as a product.

That means,

The mole ratio between the $AlCl_3:Br_2:AlBr_3:Cl_2$ are $2:3:2:3$ respectively.

Thus, the mole ratio for aluminium chloride to chlorine is, 2 : 3