Question

what is the answer for y = x2 + 8x – 3

Answer 1

To find a solution for the equation, substitute a number in for x. Let's say x=1
y=1^2+8(1)-3
y=1+8-3
y=9-3
y=6
A solution to the equation would be (1,6)

Answer 2

This answer is only a suggestion.
If you need the zeros:

$y=x^2+8x-3$
$\Delta=64+12=76$
$\sqrt{\Delta}=2\sqer{19}$
$x_1=\frac{-8-2\sqrt{19}}{2}=\frac{2(-4-\sqrt{19})}{2}=-4-\sqrt{19}$
$x_2=\frac{-8+2\sqrt{19}}{2}=\frac{2(-4+\sqrt{19})}{2}=-4+\sqrt{19}$

If you want the vertex:
$p=\frac{-8}{2}=-4$
$q=\frac{-76}{4}=-19$
$V(-4;-19)$

:)