Respuesta :
[tex]\bf \textit{volume of a pyramid}\\\\
V=\cfrac{1}{3}Bh\qquad
\begin{cases}
B=\textit{base area}\\
h=height\\
----------\\
B=3\\
V=12
\end{cases}\implies 12=\cfrac{1}{3}\cdot 3h[/tex]
solve for "h"
solve for "h"
Answer:
Volume(V) of a right square pyramid is given by:
[tex]V = \frac{1}{3} a^2h[/tex]
where,
a is the base length and h is the height respectively.
As per the statement:
A square pyramid that has a volume of 12 cubic feet and a base length of 3 feet.
⇒V = 12 cubic feet and a = 3 feet
Substitute these in [1] we have';
[tex]12 = \frac{1}{3} \cdot 3^2 \cdot h[/tex]
⇒[tex]12 = \frac{1}{3} \cdot 9 \cdot h[/tex]
⇒[tex]12 = 3 \cdot h[/tex]
Divide both sides by 3 we have;
4 = h
or
h = 4 feet
Therefore, the height of of a square pyramid is, 4 feet