Respuesta :

[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh\qquad \begin{cases} B=\textit{base area}\\ h=height\\ ----------\\ B=3\\ V=12 \end{cases}\implies 12=\cfrac{1}{3}\cdot 3h[/tex]

solve for "h"

Answer:

Volume(V) of a right square pyramid is given by:

[tex]V = \frac{1}{3} a^2h[/tex]

where,

a is the base length and h is the height respectively.

As per the statement:

A square pyramid that has a volume of 12 cubic feet and a base length of 3 feet.

⇒V = 12 cubic feet and a = 3 feet

Substitute these in [1] we have';

[tex]12 = \frac{1}{3} \cdot 3^2 \cdot h[/tex]

⇒[tex]12 = \frac{1}{3} \cdot 9 \cdot h[/tex]

⇒[tex]12 = 3 \cdot h[/tex]

Divide both sides by 3 we have;

4 = h

or

h = 4 feet

Therefore, the height of of a square pyramid is, 4 feet

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