Question

How do you solve the equation u^2-8=7u by factoring?

Answer 1

$u^2-8=7u$
$u^2-7u-8=0$
$u^2-8u+u-8=0$
$u(u-8)+(u-8)=0$
$(u-8)(u+1)=0$
$\boxed{u=8\lor u=-1}$