Rearrange the equation:
[tex] \frac{0.0562}{2} * log( \frac{0.1+x}{1.5 - x}) = 0.527 - 0.46 = 0.067 [/tex]
Isolate the log on its own
[tex]log (\frac{0.1 + x}{1.5 - x}) = \frac{0.067*2}{0.0562} = 2.42 (2dp) [/tex]
To get rid of the log you must do 10^2.42
[tex] \frac{0.1 +x}{1.5-x} = 10^{2.42} = 242.29 (2dp) [/tex]
Then multiply both sides by (1.5 - x)
[tex]0.1 +x = 242.29(1.5-x) [/tex]
[tex]0.1 + x = 363.44 - 242.29x[/tex]
Solve normally
[tex]243.29x = 363.34
x = 363.34/243.29
x= 1.49344
x= 1.49 (2dp)[/tex]
Hope that helps. Please send me a message if there's patchy bits. Also I'm sure you'll figure this out, but just in case, anywhere I've put down a 2dp shows that I've rounded the number to 2 decimal places. It becomes a pain to deal with otherwise.
