Question

write an equation for the line that is parallel to the given line and passes through the given point
y=5x+10; (2,14)


y = 1/5x+4
y = 5x+4
y = -1/5x - 4
y=5x-68

Answer 1

Y = 5x+4. The slope is the same, 5, making them parallel, and when you plug in 2 for x you get 14

Answer 2

Answer:

$y = 5x+4$

Step-by-step explanation:

For this case we have the following equation:

$y = 5x +10$

And we want a line parallel to this one that passes thourgh the point (2,14). In order to satisfy this we need that condition:

$m_1 = m_2 =5$

Where $m_1 = 5$ on this case for the original slope, and if we solve for $m_2$ we got:

$m_2 = 5$

And now since we have the new slope we can solve for the value of b like this:

$14 = 5*(2) + b$

And if we solve for b we got:

$b = 14- 10= 4$

And then our equation parallel is given by:

$y = 5x+4$