In the right triangle below, tanA = 0.45. What is the approximate length of AB?
10 units
13 units
20 units
22 units

Answer with Step-by-step explanation:
We are given that:
tanA = 0.45
tanA= [tex]\dfrac{Perpendicular}{Base}[/tex]
= [tex]\dfrac{BC}{AC}[/tex]
⇒ [tex]\dfrac{BC}{AC}[/tex]=0.45
⇒ [tex]\dfrac{9}{AC}[/tex]=[tex]\dfrac{45}{100}[/tex]
⇒ [tex]\dfrac{9}{AC}[/tex]=[tex]\dfrac{9}{20}[/tex]
⇒ AC= 20
Hence, by pythagoras theorem
AB²=AC²+BC²
AB²=20²+9²
AB²=481
⇒ AB=21.9 units
Hence, the approximate length of AB is:
22 units