Question

A bag of marbles contains 5 red, 3 blue,2 green and 2 yellow marbles.

What is the probability that you choose a blue marble and then another blue marble, assuming you replace the first marble??
A.1/24
B.1/16
C.1/2
D.3/4
Please help

Answer 1

i would definitely say the probability is 1/6 

Answer 2

Answer: $\frac{1}{16}$

Step-by-step explanation:

Given: The number of blue marbles = 3

The total number of marbles = $5+3+2+2=12$

Then the probability that you choose a blue marble and then another blue marble, assuming you replace the first marble =

$=\frac{3}{12}\times\frac{3}{12}=\frac{1}{16}$

Hence, the the probability that you choose a blue marble and then another blue marble, assuming you replace the first marble =$\frac{1}{16}$