Respuesta :

8828
it is 27, 783. Hope this helps

Answer: 27783

Step-by-step explanation:

Given : The number of toppings for pizza= 21

If repetition of toppings is allowed,  then the number of different 3-topping combinations will be :-

[tex]21\times21\times21=9261[/tex]

Also, the number of choices for crust = 3

Then, the number if different 3-topping pizzas can be made if toppings can be selected more than once will be :_

[tex]9261\times3=27783[/tex]

Hence, the number of different 3-topping pizzas can be made = 27783

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