Question

The quantity of soda consumed per week at a soda fountain is 34 liters, with a standard deviation of 5.8 liters. If any 80 weeks were sampled randomly, what would be the margin of error of the sample mean?

Answer 1

5.8/ sqrt 80=0.648 I think you are asking for the standard margin 
Hope this works

Answer 2

Answer:

The margin of error of the sample mean is 0.648.

Step-by-step explanation:

The standard error(margin of error) of a sample mean is given by the following formula:

$SE = \frac{s}{\sqrt{n}}$

In which s is the standard deviation of the sample and n is the size of the sample.

In this problem, we have that:

$s = 5.8, n = 80$

So

$SE = \frac{5.8}{\sqrt{80}} = 0.648$

The margin of error of the sample mean is 0.648.