What is the measure of angle BCD?
m∠BCD =___ degrees

we know that
the sum of the measures of the exterior angles of a polygon is always [tex]360\°[/tex]
so
Find the external angle in C
[tex]external\ angle (C)=360\°-(149\°+25\°+146\°)=40\°[/tex]
[tex]external\ angle (C)+internal\ angle (BCD)=180\°[/tex] -----> by supplementary angles
[tex]internal\ angle (BCD)=180\°-external\ angle (C)[/tex]
[tex]internal\ angle (BCD)=180\°-40\°[/tex]
[tex]internal\ angle (BCD)=140\°[/tex]
therefore
the answer is
[tex]angle (BCD)=140\°[/tex]
Answer:
140º
Step-by-step explanation:
Got right on test