Question

There are 4 red marbles, 2 white marbles, and 2 black marbles in a bag. Consider the following compound events. What is the probability that Maria will pick two red marbles if she returns the first marble to the bag?   p((red))p((red))=(4/8)(4/8) answer: A.3/14 B.1/4 C.4/8 D.4/7 
What is the probability that Maria will pick up two red marbles in a row if she did not replace the first marble in the bag?   p((red))p((red))=(4/8)(3/7) answers: A.1/8 B.3/14 C.4/12 D.3/8

Answer 1

Answer:  The correct options are

(B) $\dfrac{1}{4}$

(B) $\dfrac{3}{14}.$

Step-by-step explanation:  Given that there are 4 red marbles, 2 white marbles, and 2 black marbles in a bag.

We are to find the probability that Maria will pick two red marbles if she returns the first marble to the bag.

The probability is given by

$p=P(red)P(red)=\dfrac{4}{4+2+2}\times\dfrac{4}{4+2+2}=\dfrac{4}{8}\times\dfrac{4}{8}=\dfrac{1}{2}\times\dfrac{1}{2}=\dfrac{1}{4}.$

Thus, (B) is the correct option.

Also, we are to find the probability that Maria will pick up two red marbles in a row if she did not replace the first marble in the bag.

The probability is given by

$p=P(red)P(red)=\dfrac{4}{4+2+2}\times\dfrac{3}{3+2+2}=\dfrac{4}{8}\times\dfrac{3}{7}=\dfrac{3}{14}.$

Thus, (B) is the correct options.

Answer 2

Answer:

A) 1/4

B) 3/14

Step-by-step explanation:

See photo :)