Question

A pool measures 12.3 feet by 16.6 feet.if the longer wall of the pool has a diagonal of 17.8 feet, what is the volume of the pool? (Round to the nearest tenth) a) 1306.8 ftb)1401.2c)1891.1d)3634.4 ft

Answer 1

c^2= b^2 + a^2

17.8^2= b^2 + 16.6^2

b= 6.42495

V= 16.6*12.3*6.4= 1,306.752

= 1,306.8 ft^3

Answer 2

Answer:

Option A is correct.

Step-by-step explanation:

The dimensions of the pool are = 12.3 feet by 16.6 feet and the longer wall of the pool has a diagonal of 17.8 feet. We can find the depth of the pool using Pythagorean theorem. Let the depth be represented by x.

$a^{2}+b^{2}=c^{2}$

$17.8^{2}=x^{2} +16.6^{2}$

$316.84=x^{2} +275.56$

$316.84-275.56=x^{2}$

$x^{2} =41.28$

x = 6.4

Depth is 6.4 feet.

Volume of the pool is given by = length*width*depth

= $16.6\times12.3\times6.4=1306.75$ ≈ 1306.8 cubic feet