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I believe x=3.
If you plug in 0 for X in x+y=3, you get that y=3.
When you plug it in (2x+5(3)=21) you get 2x+15=21.
When you subtract 15 from 21, you're left with 2x=6. Divide both sides by 2, and x=3.
I hope I was able to help. Best of luck.
If you plug in 0 for X in x+y=3, you get that y=3.
When you plug it in (2x+5(3)=21) you get 2x+15=21.
When you subtract 15 from 21, you're left with 2x=6. Divide both sides by 2, and x=3.
I hope I was able to help. Best of luck.
Value of variable 'x' is (-2).
Equations given in the question are,
2x + 5y = 21 -------(1)
x + y = 3 ------(2)
Multiply equation (2) by 2 then subtract it from equation (1),
(2x + 5y) - (2x + 2y) = 21 - 2×3
2x + 5y - 2x - 2y = 21 - 6
3y = 15
y = 5
By substituting the value of 'y' in equation (2),
x + 5 = 3
x = 3 - 5
x = -2
Therefore, value of variable 'x' will be (-2).
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