Respuesta :

[tex]\bf \textit{surface area of a sphere}\\\\ S=4\pi r^2\qquad \begin{cases} r=radius\\ -----\\ S=16\pi \end{cases}\implies 16\pi =4\pi r^2\implies \sqrt{\cfrac{16\pi }{4\pi }}=\boxed{r} \\\\\\ \textit{volume of a sphere}\\\\ V=\cfrac{4}{3}\pi r^3\implies V=\cfrac{4}{3}\pi \cdot \boxed{\sqrt{\cfrac{16\pi }{4\pi }}}[/tex]

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