Respuesta :
This is exponential growth/decay type problem...
F=Ir^t, F=final value, I=initial value, r=rate, t=time, in this case I=1250 and r=(1-.045)=0.955 so
F=1250(.955)^t and we want to find t for when F=800
800=1250(.955)^t
.64=.955^t take the natural log of both sides...
ln.64=t ln.955
t=(ln.64)/ln.995
t≈9.69 weeks
t≈9.69 weeks (to nearest hundredth of a week)
F=Ir^t, F=final value, I=initial value, r=rate, t=time, in this case I=1250 and r=(1-.045)=0.955 so
F=1250(.955)^t and we want to find t for when F=800
800=1250(.955)^t
.64=.955^t take the natural log of both sides...
ln.64=t ln.955
t=(ln.64)/ln.995
t≈9.69 weeks
t≈9.69 weeks (to nearest hundredth of a week)
800=1250(1-0.045)^t
Solve for t
t=log(800÷1,250)÷log(1−0.045)
t=9.7 weeks
Check
A=1,250×(1−0.045)^(9.7)
A=799.7=800
Solve for t
t=log(800÷1,250)÷log(1−0.045)
t=9.7 weeks
Check
A=1,250×(1−0.045)^(9.7)
A=799.7=800