Answer:
the average rate of change for f(x) from x = 0 to x = 10 is, 21
Step-by-step explanation:
Average rate(A(x)) of change of f(x) over interval [a,b] is given by:
[tex]A(x) = \frac{f(b)-f(a)}{b-a}[/tex]
As per the statement:
The table of values represents a quadratic function.
We have to find the average rate of change for f(x) from x = 0 to x = 10
At x = 0
⇒f(0) = -6
at x = 10
⇒f(10) = 204
Substitute these in [1] we have;
[tex]A(x) = \frac{f(10)-f(0)}{10-0}[/tex]
⇒[tex]A(x) = \frac{204-(-6)}{10}[/tex]
⇒[tex]A(x)=\frac{210}{10}[/tex]
Simplify:
A(x) = 21
Therefore, the average rate of change for f(x) from x = 0 to x = 10 is, 21