Question

An object with a mass of 100 grams (0.100 kg) is dropped from a certain height and has a velocity of 60 meters/second. If the potential energy of this object is 179.99 joules, how high was the object when it was dropped?

Answer 1

KE=PE
1/2*m*V^2=mgh
1/2*0.100*(60)^2=0.100*10*h
0.05*3600=h
180 meters=h

Answer 2

Explanation :

Given that,

Mass of the object, m = 100 g = 0.1 kg

Velocity with which it was dropped, v = 60 m/s

Potential energy of the object, PE = 179.99 J

The expression for the potential energy is given by :

$PE=mgh$

h is the reference height.

$h=\dfrac{PE}{mg}$

$h=\dfrac{179.99\ J}{0.1\ kg\times 9.8\ m/s^2}$

$h=183.67\ m$

The object is placed at a height of 183.67 m.

Hence, this is the required solution.