Hey!
Hope this helps...
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First we would re-arrange these 2 sets of numbers from least to greatest...
Table 1 (Original): 2,4,8,8,2,6,4,8,3
Table 2 (Original): 2,6,3,5,2,4,6,3,2
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Table 1 (Re-Arranged): 2,2,3,4,4,6,8,8,8
Table 2 (Re-Arranged): 2,2,2,3,3,4,5,6,6
Now we want to find the MIDDLE NUMBER of both tables...
Table 1 (Middle Number): 4
Table 2 (Middle Number): 3
Now we have 4 tables the numbers on the left and right of 4 in Table 1, and the numbers on the left and the right of 3 on Table 2 (Do not include 3 nor 4 in those tables)
Table 1.1 (left of 4): 2,2,3,4
Table 1.2 (right of 4): 6,8,8,8
Table 2.1 (left of 3): 2,2,2,3
Table 2.2 (right of 3): 4,5,6,6
The numbers that are underlined and italicized are the numbers we have to find the average of...
Table 1.1 (avg): (2+3)/2 > 5/2 > 2.5
Table 1.2 (avg): (8+8)/2 > 16/2 > 8
Table 2.1 (avg): (2+2)/2 > 4/2 > 2
Table 2.2 (avg): (5+6)/2 > 11/2 > 5.5
IQR (Interquartile Range) of Table 1: 8 - 2.5 = 5.5
IQR of Table 2: 5.5 - 2 = 3.5
So the answer to your question is A.) The interquartile range for Company A employees is 2 more than the interquartile range for Company B employees.
