Respuesta :

The half-life  of carbon-14 is equal to 5730 years. The amount of substance with half-life h at any time t is equal to,
                       At = (Ao) x (1 - 0.5)^(t/h)
Substituting, 
                    At/Ao = 0.67 = 0.5^(t/5730)
The value of t from the equation is 3310.6 years. 

The age of the fossil is mathematically given as

3310.6 years.  

The age of the fossil

Question Parameters:

Generally the equation for the substance with half-life h at any time t   is mathematically given as

At = (Ao) x (1 - 0.5)^(t/h)

Therefore

At/Ao = 0.67 = 0.5^(t/5730)

t=3310.6 years.  

Therefore, the value of t  is 3310.6 years.  

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