Respuesta :
The half-life of carbon-14 is equal to 5730 years. The amount of substance with half-life h at any time t is equal to,
At = (Ao) x (1 - 0.5)^(t/h)
Substituting,
At/Ao = 0.67 = 0.5^(t/5730)
The value of t from the equation is 3310.6 years.
At = (Ao) x (1 - 0.5)^(t/h)
Substituting,
At/Ao = 0.67 = 0.5^(t/5730)
The value of t from the equation is 3310.6 years.
The age of the fossil is mathematically given as
3310.6 years.
The age of the fossil
Question Parameters:
Generally the equation for the substance with half-life h at any time t is mathematically given as
At = (Ao) x (1 - 0.5)^(t/h)
Therefore
At/Ao = 0.67 = 0.5^(t/5730)
t=3310.6 years.
Therefore, the value of t is 3310.6 years.
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