Respuesta :

Wouldn't that be reflection
First, lets' see all the points that are plotted on the preimage and match them to the corresponding points on the image.

A(-4,5) | A'(4,5)
C(-5,1) | C'(-5,1)
T(-1,3) | T'(1,3)

We notice in the x-coordinates of each point and it's corresponding point that it becomes negative (for example, on point A, the x-coordinate is 4 and on point A', th point is -4). Therefore, we can write the rule (x,y) -> (-x,y).

(The "->" is an arrow)

:)
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