Respuesta :

hello :
2sin2x+√3=0
2sin2x= -√3
sin2x= -√3/2
sin2x= sin(-π/3)
general solution in R is :  (2x =-π/3 +2kπ) or (2x =π-π/3 +2kπ)
(x= -π/6 +kπ) or ( x=π/3+kπ).....k∈ Z