Question

What is the result of changing the dielectric in a capacitor to a dielectric with a larger dielectric constant?
A. The capacitor will have a lower charge at a given potential energy.
B. The capacitor will have a higher potential difference at a given potential energy.
C. The capacitor can store less potential energy at a given potential difference.
D. The capacitor can store more charge at a given potential difference.

Answer 1

Q=C·V--->The dielectric increases the capacity, then for a given potential difference Q is increased which means more charge is stored. The correct answer is D

Answer 2

Answer:   D. The capacitor can store more charge at a given potential difference.

Explanation:

The capacitance of a capacitor is given by:

$C = \frac{k\epsilon_o A}{d}$

Where, k is the dielectric constant.

When a dielectric is replaced with another having larger dielectric constant, the value of the capacitance increases.

The charge stored by the capacitor is given by:

Q = C V

where V is the voltage.

Thus, with increase in value of capacitance, the charge stored by the capacitor increases at a given potential difference.