Question

The image produced by an object is –10.0 cm from a concave mirror that has a focal length of 5.0 cm. The distance of the object from the mirror, rounded to the nearest whole centimeter, is __cm.

Answer 1

Given:
Focal length: 5.0 cm
image produced: -10.0 cm

mirror equation:   1/di + 1/do = 1/f

Look for the actual distance of the object from the mirror. Solve for do.

1/do + 1/(-10) = 1/5
1/do = 1/5 + 1/10
1/do = (1/5 * 2/2) + (1/10 * 1/1)
1/do = 2/10 + 1/10
1/do = 3/10
10 = 3do
10/3 = do
3.33 = do

The distance of the object from the mirror, rounded to the nearest centimeter is 3 cm.

Answer 2

The object distance (do), image distance (di), and focal length (f) are all expressed using the mirror equation. The object's distance from the mirror is 3 centimeters.

What is a mirror equation?

The object distance (do), image distance (di), and focal length (f) are all expressed using the mirror equation.

If you know the object distance, object height, and focal length, you may combine these two equations to get information about the image distance and height. It is given by,

$\frac{1}{d_i} +\frac{1}{d_0}= \frac{1}{f}$

Object distance (do) =?

Image distance (di)= -10 cm

Focal length (f) = 5.0 cm

On substituting the values

$\frac{1}{d_i} +\frac{1}{-10}= \frac{1}{5}$

$\frac{1}{d_i} =\frac{1}{10}+ \frac{1}{5}$

$\frac{1}{d_0} = \frac{3}{10}$

$d_0$= 3.33  cm

$d_0$= 3 cm

Hence the object's distance from the mirror is 3 centimeters, rounded to the closest whole centimeter.

To learn more about the mirror equation refer to the link;

https://brainly.com/question/3229491