Question

What is the specific heat of silicon if it takes 192J to raise the temperature of 45.0g of Si by 6.0oC?

Answer 1

Q=cmt
c=192/0.045 × 6=711,(1)

Answer 2

Answer: $0.711J/g^0C$

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed= 192 Joules

m= mass of silicon (Si) = 45.0 g

c = specific heat capacity = ?

Change in temperature ,$\Delta T=T_f-T_i=6^0C$

Putting in the values, we get:

$192=45.0\times c\times 6^0C$

$c=0.711J/g^0C$

The specific heat of silicon is $0.711J/g^0C$