Respuesta :
We are given
f(x) = 6 - x
and we are asked for the definite integral over 3, 5
Taking the integral
∫f(x) = 6x - x²/2
applying the limits
6(3) - 6²/2 - (6(5) - 5²/2)
The answer is 17.5
f(x) = 6 - x
and we are asked for the definite integral over 3, 5
Taking the integral
∫f(x) = 6x - x²/2
applying the limits
6(3) - 6²/2 - (6(5) - 5²/2)
The answer is 17.5
Answer:
The integration of the given function over 3 to 5 is 8.
Step-by-step explanation:
we have to find the integration of a function f(x)=6-x from 3 to 5 i.e. we need to find definite integration of the function f(x)=6-x.
[tex]\int_{3}^{5}6-x=6\cdot5-\frac{25}{2}-6\cdot3+\frac{9}{2}[/tex]
[tex]\int_{3}^{5}6-x=30-\frac{25}{2}-18+\frac{9}{2}[/tex]
[tex]\int_{3}^{5}6-x=30-18-\frac{25}{2}+\frac{9}{2}[/tex]
[tex]\int_{3}^{5}6-x=12-8=4[/tex]
Hence, the desired result is 8.