Answer: Option 'B' is correct.
Step-by-step explanation:
Since we have given that
∠1 = ∠4
∠2 = ∠3
And sum of the measures of the four angles = 140°
According to question, it becomes,
[tex]\angle 1+\angle 2+\angle 3+\angle 4=140^\circ[/tex]
Measure of ∠3 is 8 less than the measure of ∠4.
Let the measure of ∠4 be 'x'.
So, the measure of ∠3 would be 'x-8'.
∠1 = x and ∠2 = x-8
So, put all the values in the above equation:
[tex]x+x+x-8+x-8=140^\circ\\\\4x-16=140^\circ\\\\4x=140+16\\\\4x=156^\circ\\\\x=\dfrac{156}{4}\\\\x=39^\circ[/tex]
So,
[tex]\angle 2=39-8=31^\circ\\\\\angle 3=39-8=31^\circ\\\\\angle 1=x=39^\circ[/tex]
So, [tex]\angle 2+\angle 3+\angle 4=31^\circ+31^\circ+39^\circ=101^\circ[/tex]
Hence, Option 'B' is correct.