Question

Find the 20th term of an arithmetic sequence with a first term of 3 and a common difference of 5.

Answer 1

nth term = a + (n-1)d where a = first term and d = common difference just plug in your values (note n = 20)

Answer 2

Answer:  The required 20-th term of the given arithmetic sequence is 98.

Step-by-step explanation:  We are given to find the 20th term of an arithmetic sequence with first term 3 and common difference 5.

We know that

the n-th term of an arithmetic sequence with first term a and common difference d is given by

$a_n=a+(n-1)d.$

For the given arithmetic sequence, we have

first term, a = 3

and

common ratio, d = 5.

Therefore, the 20-th term pf the arithmetic sequence will be

$a_{20}=a+(n-1)d=3+(20-1)\times5=3+19\times5=3+95=98.$

Thus, the required 20-th term of the given arithmetic sequence is 98.