Question

if f(1) = 0 what are all the roots of the function f(x)=x^3+3x^2-x-3 use the remainder theorem.
A. x = –1, x = 1, or x = 3
B. x = –3, x = –1, or x = 1
C. x = –3 or x = 1
D. x = –1 or x = 3

Answer 1

Answer:

Answer Is B trust me Just took the test

Step-by-step explanation:

Answer 2

The roots of the function  are x = –3, x = –1. Option B is correct

Given the polynomial functions:

$f(x)=x^3+3x^2-x-3$

To get the zeros of the function, we will equate the function to zero and factorize as shown:

$x^3+3x^2-x-3=0\\x^2(x+3)-1(x+3) =0\\(x^2-1)(x+3)=0\\(x+1)(x-1)(x+3) =0\\x+1 = 0, \ x-1 = 0, and \ x + 3 = 0\\x = -1, 1 and -3$

Hence the roots of the function  are x = –3, x = –1, or x = 1

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