Respuesta :
f(x) = x^2 is a parabola with vertex at the origin (0,0).
f(x) = x^2 - 5 is a parabola shifted down 5 units so it's vertex would be at (0, -5)
The correct answer is Letter B
f(x) = x^2 - 5 is a parabola shifted down 5 units so it's vertex would be at (0, -5)
The correct answer is Letter B
Answer:
Option B The graph of [tex]f(x)-5[/tex] is a vertical shift of [tex]f(x)=x^{2}[/tex] five units down.
Step-by-step explanation:
we have
[tex]f(x)=x^{2}[/tex]
Is a vertical parabola open upward with the vertex at [tex](0,0)[/tex]
Let
[tex]g(x)=f(x)-5[/tex]
so
[tex]g(x)=x^{2}-5[/tex]
Is a vertical parabola open upward with the vertex at [tex](0,-5)[/tex]
The rule of the translation of f(x)-----> g(x) is equal to
[tex](x,y)------> (x.y-5)[/tex]
That means-----> The translation is [tex]5[/tex] units down
therefore
The graph of [tex]f(x)-5[/tex] is a vertical shift of [tex]f(x)=x^{2}[/tex] five units down.